Answer:
The car will be traveling at 24.2 m\s.
Explanation:
The first relationship we can estabilish between the measures is:
[tex]F = ma[/tex]
In which F, in N, is the force, m in kg is the mass and a is the accelation.
In this problem, we have that:
[tex]F = 1260, m = 854[/tex]
So
[tex]F = ma[/tex]
[tex]1260 = 854a[/tex]
[tex]a = \frac{1260}{854}[/tex]
[tex]a = 1.48[/tex]
We also can relate the speed to the accelaration, by the following formula:
[tex]v = v_{0} + at[/tex]
In which v is the speed, [tex]v_{0}[/tex] is the initial speed, a is the acceleration and t is the time.
We have that, [tex]v_{0} = 18.1, a = 1.48, t = 4.1[/tex]
So:
[tex]v = v_{0} + at[/tex]
[tex]v = 18.1 + 1.48*4.1[/tex]
[tex]v = 24.2 m\s[/tex]
The car will be traveling at 24.2 m\s.
