Answer:[tex]\alpha =15 rad/s^2[/tex]
Explanation:
Given
mass of sphere[tex]\left ( m\right )=215 g[/tex]
diameter[tex]\left ( d\right )=3.10 cm[/tex]
Friction Force=0.02 N
here friction force will provide torque
thus [tex]f_r\times r=I\times \alpha [/tex]
[tex]0.02\times r=\frac{2mr^2}{5}\times \alpha [/tex]
[tex]\alpha =\frac{0.02\times 5\times r}{2\times m\times r^2}[/tex]
[tex]\alpha =\frac{5\times 0.02}{2\times 0.215\times 1.55\times 10^{-2}}[/tex]
[tex]\alpha =15 rad/s^2[/tex]
