Answer:
U = 1794.005 × 10⁶ J
Explanation:
Data provided;
Capacitance of the original capacitor, C = 1.27 F
Potential difference applied to the original capacitor, V = 59.9 kV
= 59.9 × 10³ V
Now,
The Potential energy (U) for the capacitor is calculated as:
Potential energy of the original capacitor, U = [tex]\frac{\textup{1}}{\textup{2}}[/tex] × C × V²
on substituting the respective values, we get
U = [tex]\frac{\textup{1}}{\textup{2}}[/tex] × 1.27 × ( 59.9 × 10³ )²
or
U = 1794.005 × 10⁶ J
