Answer:
2025KJ/kg
Explanation:
Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)
through prior knowledge of two other properties such as pressure and temperature.
in this case we can found the specific internal energy using the quality (0.77) and the pressure, with this formula
U=Uf+(Ufg)X
Uf=innternal energy at x=0 p=1bar=417.4KJ/kg
Ufg= internal energy of evaporation at a pressure of 1 bar=2088KJ/kg
x=quality=0.77
Solving
U=417.4+(2088)0.77=2025KJ/kg
