ANSWER:
The slope of the given equation is -2 and a point on the given line is (-1, 3)
SOLUTION:
Given, linear equation in two variables is y – 3 = -2(x + 1) ----- eqn (1)
We need to find the slope of the given equation and a point through which the given line passes.
Given equation is in the form of point slope form .i.e [tex]\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right)[/tex] --- eqn 2
where,"m" is the slope of the line
[tex]\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)[/tex] is point on that line.
Now, by comparing (1) and (2)
m = -2
[tex]x_{1}=-1[/tex]
[tex]y_{1}=3[/tex]
so, the slope of the given equation is -2 and a point on the given line is (-1, 3)
Answer: slope: − 2
y-intercept: ( 0 , 1 )
x y 0 1 1 − 1
Step-by-step explanation: Graph the line using the slope and y-intercept, or two points.
