69angel69
contestada

A ball is thrown straight upward at 17 m/s.
b) What height does it reach, assuming it started at zero height?

Respuesta :

Answer:

≈ 14.74489m

Explanation:

In order to find the max height we can use the distance equation:

[tex]x_t = \frac{v_f^2-v_i^2}{2a}[/tex]

And because we can assume we are on Earth and that once it has reached its maximum height the vf is 0m/s, we can plug in our numbers:

[tex]x_t = \frac{0^2-17^2m^2/s^2}{2(-9.8m/s^2)}[/tex]

[tex]x_t = \frac{-17^2m^2/s^2}{-19.6m/s^2)}[/tex]

[tex]x_t = \frac{289m}{19.6}[/tex]

[tex]x_t \approx 14.74489m[/tex]