Answer:
The answer to your question is: 14 g of N₂
Explanation:
Data
MW N2 = 14
MW H2 = 1
MW NH3 = 17
N₂(g) + 3H₂(g) ---> 2NH₃(g).
28g 6g 34g
28 g of N₂ -------------------- 6 g of H₂
x -------------------- 3 g of H₂
x = (3 x 28) / 6
x = 14 g of N₂
A 14gram sample of N₂ requires 3.0 g of H₂ for complete reaction.
Mass of any substance will be calculated from its moles as:
n = W/M, where
W = required mass
M = molar mass
Given chemical reaction is:
N₂(g)+3H₂(g) → 2NH₃(g)
Moles of 3 gram of H₂ = 3
From the stoichiometry of the reaction, it is clear that
1 mole of N₂ = react with 3 mole of H₂
Mass of 1 mole of N₂ = 14 grams
Hence, 14 grams of nitrogen is required.
To know more about moles, visit the below link:
https://brainly.com/question/13860160
