Answer:
B = 0.10 M of AlCl₃
Explanation:
A = 0.10 M NaCl
NaCl → Na⁺ + Cl⁻
sodium chloride dissociate into sodium and chlorine ions. The one mole of NaCl produced on mole of Na⁺ and one mole of Cl⁻, so concentration of chloride ions will be 0.10 M.
B = 0.10 M of AlCl₃
AlCl₃ → Al³⁺ + 3Cl⁻
AlCl₃ dissociate into aluminium cation and chlorine anion. one mole of AlCl₃ dissociate into one mole of Al³⁺ and three mole of Cl⁻.
so concentration of chloride ion in 0.10 M solution is
0.10 × 3 = 0.3 M
C = 0.10 M MgCl₂
MgCl₂ → Mg²⁺ + 2Cl⁻
MgCl₂ dissociate into one mole of Mg²⁺ and two mole of Cl⁻.
so concentration of chloride ions in 0.10 M solution of MgCl₂ is,
2× 0.10 M = 0.20 M
d = 0.05 M CaCl₂
CaCl₂ → Ca²⁺ + 2Cl⁻
CaCl₂ dissociate into one mole of Ca²⁺ and two mole of Cl⁻, So concentration of chloride ions in 0.05 M CaCl₂ is
2× 0.05 = 0.1 M
