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A car has a mass of 1500 kg. If the driver applies the brakes while on a gravel road, the maximum friction force that the tires can provide without skidding is about 7000 N.

If the car is moving at 18 m/s, what is the shortest distance in which the car can stop safely?

Respuesta :

Hania12

Answer:

                            S =34.71 m

Explanation:

M=1500 kg

F=-7000 N

For short and safe distance stop the friction acting should be maximum

                             a(max)=[tex]\frac{F}{M}[/tex]

                                        =[tex]\frac{-7000}{1500}[/tex]

                                         =[tex]\frac{-14}{3}[/tex] m/s2

                                  u=18 m/s

Applying equation of motion

                                   v²=u²+2aS

                                   0= [tex]18^{2} +2*\frac{-14}{3}[/tex]

                                    S =34.71 m

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