Answer:
205,320
Step-by-step explanation:
If order matters this is a permutation problem (as opposed to a combination problem). The permutation of this situation is
₆₀P₃ =[tex]\frac{60!}{(60-3)!}[/tex] and is solved:
[tex]\frac{60*59*58*57!}{57!}[/tex]
The 57 factorials cancel out, leaving us with 60*59*58 which comes to 205,320 different ways to pick 3 books if order matters.
