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Two identical carts-A and B-initially are moving on frictionless air tracks. The initial speed of cart A is twice that of cart B. You then exert the same constant force on the two carts over 1 second. One second later, the change in momentum of cart A is a) non-zero and twice the change in momentum of cart B b) non-zero and the same as the change m momentum of cart B c) zero d) non-zero and half the change in momentum of cart B e) not enough information to determine

Respuesta :

Answer:

b) non-zero and the same as the change m momentum of cart B

Explanation:

As we know that change in momentum is also known as impulse which is equal to the product of force and time interval

so we will have

[tex]\Delta P = F\Delta t[/tex]

since we applied same force on two carts for small time interval of t = 1 s

so the impulse is given as

[tex]\Delta P = F(1)[/tex]

so both the carts will have same change in momentum as we know that force and time interval is same for both

so correct answer is given as

b) non-zero and the same as the change m momentum of cart B

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