Imagine you are on a spaceship. A second spaceship rockets past yours at 0.5 cc. You start a stopwatch and stop it 10 seconds later. For an astronaut in the other spaceship, the number of seconds that have ticked by during the 10 seconds on your stopwatch is____________

Respuesta :

Answer:

[tex]t=11.547\,s[/tex]

Explanation:

Given is the case of time dilation where the velocity of other spaceship is comparable to the velocity of light, i.e. relativistic velocity.

Given that:

velocity of the fast moving spaceship, [tex]v=(0.5\times c)\,\,m.s^{-1}[/tex]

where c is the velocity of light.

times according to the other spaceship, (relativistic time) [tex]t'=10\,s[/tex]

For time dilation we have the equation as:

[tex]t'=t \sqrt{1-\frac{v^2}{c^2} }[/tex]

[tex]\Rightarrow 10= t \sqrt{1-\frac{(0.5c)^2}{(c)^2} }[/tex]

[tex]t=11.547\,s[/tex]