Answer:
[tex]v_i = 36.65 m/s[/tex]
Explanation:
As we know that friction force on the car during it applied brakes is given as
[tex]F_f = -\mu mg[/tex]
so the deceleration of the car is given as
[tex]a = -\mu g[/tex]
now we can use kinematics to find the initial speed of the car
[tex]v_f^2 - v_i^2 = 2 a d[/tex]
so we will have
[tex]0 - v_i^2 = 2(-\mu g)(d)[/tex]
now plug in all the data in it
[tex]v_i^2 = 2(0.82)(9.81)(79)[/tex]
[tex]v_i = 36.65 m/s[/tex]