(Mendelian Genetics) Consider three gene pairs Aa, Bb, and Cc. The uppercase letter is the dominant allele and each gene pair assorts independently of each other. What is the probability of obtaining an offspring displaying the A B C phenotype (that is having the dominant phenotypes for each of the three genes) from a cross of Aa Bb CC X Aa Bb cc parents?

Because genes assort independently, we can analyze each of them separately in the cross, calculate the probability of getting offpsring with a dominant allele, and then multiply each of those probabilities to obtain the overall probability of having A_B_C_ progeny.

A/a

Aa x Aa ---> 3/4 A_, 1/4 aa

B/b

Bb x Bb ---> 3/4 B_, 1/4 bb

C/c

CC x cc ---> 1 C_

3/4 × 3/4 × 1 = 9/16 A_B_C_ offspring.

akposevictor akposevictor · Answer 2 · 2022-03-25T13:46:02+01:00

The probability of obtaining an offspring displaying the dominant phenotypes for each of the three genes (A_B_C_) is: 9/16.

What is a Dominant Phenotype?

A dominant phenotype is the phenotype of a trait that expresses itself over that of a recessive trait.

A dominant phenotype is always represented in the upper case for a trait.

Thus, given:

(Aa)(Bb)(CC) x (Aa)(Bb)(cc)

We would have the following outcome as shown in the Punnett square shown in the image attached below.

Thus, the probability of obtaining an offspring displaying the dominant phenotypes for each of the three genes (A_B_C_) is: 9/16.

Learn more about dominant phenotype on:

https://brainly.com/question/506198