Answer:
3/4
Step-by-step explanation:
Given that an individual uses the following gambling system at Las Vegas. He bets $ 1 that the roulette wheel will come up red
Prob of winning in one trial = 1/2
For him to go home as winner either he has to win in the I case or he loses I one and wins the second one.
Hence probability = prob he wins the Ist +prob he loses first and wins second
=[tex]\frac{1}{2} +\frac{1}{2} \frac{1}{2} \\=\frac{3}{4}[/tex]
This system will not be used because normally prob of winning will not be 1/2 but much more less than that. Hence prob of losing would be more so everyone may not use this.
