Answer:
0.07776, 0.3456,0.08704
Step-by-step explanation:
Given that a new surgical procedure is said to be successful 60% of the time
Let X be the no of successes
Then X has only two outcomes and each trial is independent of the other
Hence X is binomial with p = prob of success in a single trial = 0.60
n = Number of operations performed = 5
Prob that
a) all five operations are successful =
[tex]P(X=5)\\= (0.6)^5\\=0.07776[/tex]
(b) exactly three are successful
=[tex]P(X=3) = 5C3 (0.6)^3(0.4)^2\\= 0.3456[/tex]
(c) less than two are successful
[tex]==P(X<2)\\=P(x=0)+P(x=1)\\= (0.4)^5 + 5(0.6)(0.4)^4\\= 0.0256(0.4+3)\\=0.08704[/tex]
