Answer:
The scale of the graph shows that the point «A» , which is the radio of the circle, is allocated in (x,y)=(3,2) (one square is equal to one unit according to the picture). Then , replacing this information into a circle's equation, given by
[tex](x-s)^{2} +(y-n)^{2}=r^{2}[/tex]
where r is the radio (distance from the center of the circle to its borders) and (s, n) are the values that specify the location of the center of your circle in the axis (x, y) respectively, where r = (s, n); results in the following expression:
[tex](x-3)^{2} +(y-2)^{2}=A^{2}[/tex]
Step-by-step explanation:
- Identify the radio of your circle (A in the example)
- Identify the coordinates of the radio: A=(3,2)
- Replace the information into the circle's equation
