Answer:
Power, P = 350 watts
Explanation:
It is given that,
Mass of the person, m = 70 kg
Speed of the person, v = 5 km/h = 1.388 m/s
It is assumed that the metabolic power required is equal to that required for walking on a flat surface plus the rate of doing work for the vertical climb. Let P is the power required. It can be calculated as :
[tex]P=\dfrac{W}{t}=\dfrac{F.d}{t}[/tex]
Since, [tex]\dfrac{d}{t}=v[/tex]
Here, [tex]v=5\% \ of\ 1.388=0.0694\ m/s[/tex]
[tex]P=F\times v[/tex]
[tex]P=m\times g\times v[/tex]
[tex]P=70\times 9.8\times 0.0694[/tex]
P = 47.60 watts
It can be assumed that, the required power to walk is 300 W. So,
P = 300 W + 47.60 W
P = 347.6 W
or
P = 350 W
So, the power required is 350 watts. Hence, this is the required solution.
