Answer:
[tex]21.75[/tex]
Explanation:
[tex]n[/tex] = number of polarizers through which light pass through = 5
[tex]\theta[/tex] = Angle between each pair of adjacent polarizers
[tex]I_{o}[/tex] = Intensity of unpolarized light
[tex]I_{n}[/tex] = Intensity of transmitted beam after passing all polarizers
It is given that
[tex]\frac{I_{n}}{I_{o}}= 0.277[/tex]
we know that the intensity of light after passing through "n" polarizers is given as
[tex]I_{n} = (0.5) I_{o} Cos^{2n-2}\theta[/tex]
[tex]\frac{I_{n}}{I_{o}} = (0.5) Cos^{2n-2}\theta[/tex]
inserting the values
[tex]0.277 = (0.5)Cos^{2(5)-2}\theta[/tex]
[tex]0.554 = Cos^{8}\theta[/tex]
[tex]Cos\theta = 0.9288[/tex]
[tex]\theta = Cos^{-1}(0.9288)[/tex]
[tex]\theta = 21.75[/tex]
The angle theta between the axes of each pair of adjacent polarizers is mathematically given as
[tex]\theta = 21.75[/tex]
Question Parameter(s):
A beam of unpolarized light shines on a stack of five ideal polarizers
intensity of the initial beam by a factor of phi=0.277
Generally, the intensity of light is mathematically given as
[tex]I_{n} = (0.5) I_{o} Cos^{2n-2}\theta[/tex]
[tex]\frac{I_{n}}{I_{o}} = (0.5) Cos^{2n-2}\theta[/tex]
[tex]0.277 = (0.5)Cos^{2(5)-2}\theta[/tex]
[tex]0.554 = Cos^{8}\theta[/tex]
[tex]Cos\theta = 0.9288[/tex][tex]\theta = Cos^{-1}(0.9288)[/tex]
In conclusion angle theta is
[tex]\theta = Cos^{-1}(0.9288)[/tex]
[tex]\theta = 21.75[/tex]
Read more about Light
https://brainly.com/question/25770676
