Answer:
t = 1.68 min
S = 2.82 miles
Explanation:
Given,
The initial velocity of the vehicle, u = 0
The final velocity of the vehicle, v = 203 mph
The average acceleration of the vehicle, a = 2.93 ft/s²
= 7191.82 miles/h²
Using the first equation of motion
v = u + at
t = (v - u) / a
= (203 - 0) / 7191.82
= 0.028 h
= 100.8 s
Thus, the time taken by the vehicle to reach the final velocity is, t = 100.8 s
Using the third equations of motion
S = ut + 1/2 at²
Substituting the values
S = 0.5 x 7191.82 x (0.028)²
= 2.82 miles
Hence, the distance traveled by the vehicle, S = 2.82 miles
