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During a hard stop, a car and its passengers slow down with an acceleration of 8,0m/s^2. What magnitude force does a 50-kg passenger exert on the seat belt in such a stop?

Respuesta :

Answer:

F = 400 N

Explanation:

Given,

The acceleration of the car, a = 8 m/s²

The mass of the passenger, m = 50 Kg

The force acting on a body is equal to the product of the mass and its acceleration

                                    F = m x a   newtons

Substituting the given values in the above equation,

                                     F = 50 Kg x 8 m/s²

                                        = 400 N

Hence, the force exerted by the person on the seat belt is, F = 400 N

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