Answer:
A. [tex]\frac{3}{4}\textrm{ gal}[/tex]
Step-by-step explanation:
Given:
Volume of the cylindrical container before dilation, [tex]V_{i}=1\textrm{ gal}[/tex]
Scale factor of the dilation, [tex]SF=\frac{3}{4}[/tex]
Therefore, the volume of the dilated cylinder is given as:
[tex]V_{f}=SF\times V_{i}[/tex]
Plug in 1 gal for [tex]V_{i}[/tex] and [tex]\frac{3}{4}[/tex] for SF. Solve for [tex]V_{f}[/tex]. This gives,
[tex]V_{f}=\frac{3}{4}\times 1\\V_{f}=\frac{3}{4}\textrm{ gal}[/tex]
Therefore, the volume of the dilated cylinder is [tex]\frac{3}{4}[/tex] gallons.
