Answer:
The equation which can be used is [tex]f=2.5b[/tex] based on the graph.
Step-by-step explanation:
As the graph given is linear so we can apply linear (straight line) equations.
Equation of a straight line, [tex]y=mx+b[/tex] where [tex]m[/tex] is the slope.
We can find [tex]m[/tex] by using point-slope formula as here we can pull two co-ordinate points from the graph.
Point-slope formula,[tex]y-y_{1}=m(x-x_{1)}[/tex].
Then [tex]m=\frac{y-y_1}{x-x_1}[/tex]
Lets choose two points from the graph,we have [tex](4,10),(6,15)[/tex] in terms of [tex](x,y)[/tex].
[tex]m=\frac{15-10}{6-4} = \frac{5}{2}= 2.5 [/tex]
Now comparing our values with that of the straight line equation we can see that [tex]f=y\ and\ m=2.5[/tex]
Lets find the exact value of [tex]b\ as\ b=y-mx[/tex] putting [tex](6,15)[/tex] in the equation [tex]b=y-mx[/tex],we have [tex]b=15-2.5\times 6 = 0[/tex]
So we can say that [tex]f=2.5b[/tex] is the relevant answer which has [tex]b=0[/tex]
