This question involves the concept of the equations of motion.
a. The diver's speed at 5 m height above the water's surface will be "98.1 m/s".
b. The diver's speed at the water's surface will be "196.2 m/s".
We can use the third equation of motion to find out the speed of the diver at different heights:
[tex]2gh=v_f^2-v_i^2[/tex]
where,
g = acceleration due to gravity = 9.81 m/s²
h = height lost
v_f = final speed = ?
v_i = initial speed = 0 m/s
Therefore,
[tex]2(9.81\ m/s^2)h=v_f^2-(0\ m/s)^2\\\\v_f=\sqrt{(19.62\ m/s^2)h}[/tex]
a.
Here,
h = 5 m
Therefore,
[tex]v_f=\sqrt{(19.62\ m/s^2)(5\ m)}\\\\v_f = 98.1\ m/s[/tex]
b.
Here,
h = 10 m
Therefore,
[tex]v_f=\sqrt{(19.62\ m/s^2)(10\ m)}\\\\v_f = 196.2\ m/s[/tex]
Learn more about equations of motion here:
brainly.com/question/20594939?referrer=searchResults
The attached picture shows the equations of motion.
