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About 5% of the population has a particular genetic mutation. 1000 people are randomly selected.


Find the standard deviation for the number of people with the genetic mutation in such groups of 1000.

Respuesta :

Answer:

[tex]\simeq 6.89202[/tex]

Step-by-step explanation:

Let, X = Number of people with the genetic mutation in such groups of 1000

Here, we get a random variable X with binomial distribution with parameters

n = 1000 and p = 5 % = 0.05

So,

X [tex]\sim [/tex] bin ( 1000 , 0.05)

so V(X) or Variance(X) = [tex]n \times p \times (1 -p)[/tex]

                                     = 47.5

So, SD(X) = Standard Deviation(X) = [tex]\sqrt (47.5)[/tex]

                                                        [tex]\simeq 6.89202[/tex]

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