Answer:
number is 13
Step-by-step explanation:
Let
the digit at units place is b
the digit at tens place is a
The number is: ab
Now According to condition: The tens digit is two less than the units digit
a = b -2 ---------- eq1
From the condition: Eight times the sum of the digits of a certain two-digit number exceeds the number by 19.
8(a+b)=10a+b+19
By simplifying
Putting a= b-2
8a+8b=10(b-2)+b+19
8(b-2)+8b=10b-20+b+19
8b-16+8b=10b-20+b+19
By adding like terms we get:
5b=15
Dividing both sides by 5
b = 3
Now putting value of b in eq1
a = b - 2
a = 3 -2
a =1
hence the number is : 13
i hope it will help you!
u=3
t=u-2=1
