Respuesta :
Answer:
Normal force acting on the woman is 629.85 N.
Explanation:
Given:
Mass of the woman is, [tex]m=57\textrm{ kg}[/tex]
Net upward acceleration is, [tex]a=1.25\textrm{ }m/s^{2}[/tex]
Acceleration due to gravity, [tex]g=9.8\textrm{ }m/s^{2}[/tex]
Let the normal force acting upward be [tex]R[/tex] newtons.
Therefore, net force in the upward direction is given as:
Net force = Upward force - Downward force.
Downward force acting on the woman is her weight which is equal to [tex]mg[/tex].
Therefore, Net force = [tex]R-mg[/tex]
Now, as per Newton's second law of motion,
Net force, [tex]F_{net}=ma[/tex]
So,
[tex]R-mg=ma\\R=mg+ma\\R=m(g+a)[/tex]
Plug in 57 kg for [tex]m[/tex], 9.8 m/s² for [tex]g[/tex], and 1.25 m/s² for [tex]a[/tex]. Solve for [tex]R[/tex]. This gives,
[tex]R=57(9.8+1.25)\\R=57(11.05)=629.85\textrm{ N}[/tex]
Therefore, the normal force acting on her is 629.85 N.
Answer:
629
Explanation:
That is the answer for acellus students
