The point that divides the line from M to E in ratio 1:3 is (-7/2,8)
Step-by-step explanation:
Given points are:
M(-6,7) = (x1,y1)
E(4,11) = (x2,y2)
Let the ratio be a:b
Then from 1:3
a=1
b=3
The formula for finding the point that divides the line segment into ratio a:b is:
[tex](\frac{bx_1+ax_2}{a+b},\frac{by_1+ay_2}{a+b})\\Putting\ the\ values\\(\frac{(3)(-6)+(1)(4)}{1+3},\frac{(3)(7)+(1)(11)}{1+3})\\(\frac{-18+4}{4},\frac{21+11}{4})\\(\frac{-14}{4},\frac{32}{4})\\(\frac{-7}{2},8)[/tex]
Hence,
The point that divides the line from M to E in ratio 1:3 is (-7/2,8)
Keywords: Coordinate Geometry, Lines
Learn more about coordinate geometry at:
- brainly.com/question/3126500
- brainly.com/question/3306327
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