Answer:
The velocity with which the ball hit the wall is 5 m/s
Step-by-step explanation:
Given as :
The mass of rock = 4 kg
The kinetic energy of the rock = 50 J = 50 kg [tex][m^{-1}s]^{2}[/tex]
Let The speed of rock = V
So, From Kinetic energy formula
Kinetic energy ( K E ) = [tex]\frac{1}{2}\times mass\times velocity^{2}[/tex]
Or, 50 J = [tex]\frac{1}{2}\times 4\times v^{2}[/tex]
Or, [tex]\frac{50\times 2}{4}[/tex] = V²
Or, 25 = V²
∴ V = [tex]\sqrt{25}[/tex] = 5 m/s
Hence The velocity with which the ball hit the wall is 5 m/s Answer
