Answer: [tex]-9.5 kg m/s[/tex]
Explanation:
The change in momentum [tex]\Delta p[/tex] is given by:
[tex]\Delta p=p_{2}-p_{1}[/tex] (1)
Where:
[tex]p_{1}=m V_{1}[/tex] is the initial momentum of the baseball, being [tex]m=0.1 kg[/tex] and [tex]V_{1}=40 m/s[/tex]
[tex]p_{2}=m V_{2}[/tex] is the final momentum of the baseball, being [tex]V_{2}=-55 m/s[/tex] because it is in the oppossite direction
Then (1) is rewritten as:
[tex]\Delta p=m V_{2} - m V_{1}= m(V_{2} - V_{1})[/tex] (2)
[tex]\Delta p=0.1 kg(-55 m/s - 40 m/s)[/tex] (3)
Finally:
[tex]\Delta p=-9.5 kg m/s[/tex]
