Answer:
5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity
Explanation:
The concept to solve this problem is given by Energy Transferred, the equation is given by,
[tex]Q = mc\Delta T[/tex]
Where,
Q= Energy transferred
m = mass of water
c = specific heat capacity
[tex]\Delta T =[/tex] Temperature change (K or °C)
Replacing the values where mass is 50g and temperature is 80°C to 0°C we have,
[tex]Q = mc\Delta T[/tex]
[tex]Q = 50*0.11*(80-0)[/tex]
[tex]Q = 440cal[/tex]
Then we can calculate the heat absorbed by m grams of ice at 0°C, then
[tex]Q_2 = mL = 80*m[/tex]
How Q_1=Q_2, so
[tex]80m=440[/tex]
[tex]m=\frac{440}{80}[/tex]
[tex]m = 5.5g[/tex]
Then 5.5g of ice melts when a 50g chunk of iron at 80°C is dropped into a cavity
