Answer:
5.3 hours
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
a = Acceleration
m = Mass
Force
[tex]F=2T\\\Rightarrow F=2\times 50000\\\Rightarrow F=100000\ N[/tex]
The force generated by the jet engines is 100000 N
From Newton's Second law
[tex]F=ma\\\Rightarrow a=\frac{F}{m}\\\Rightarrow a=\frac{100000}{3.2\times 10^8}\\\Rightarrow a=0.0003125\ m/s^2[/tex]
Equation of motion
[tex]v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{6-0}{0.0003125}\\\Rightarrow t=19200\ s=\frac{19200}{3600}=5.3\ hours[/tex]
It will take 5.3 hours to reach a speed of 6 m/s
The time taken will be "5.3 hours".
According to the question,
Final velocity, v = 6.0 m/s
Initial velocity, u = 0 m/s
Mass, m = 3.2 x 10⁸ kg
We know that,
Force, F = 2T
By substituting the values,
= 2 x 50000
= 100000 N
By using Newton's Second law,
→ F = ma
or,
→ a = [tex]\frac{F}{m}[/tex]
= [tex]\frac{100000}{3.2\times 10^8}[/tex]
= 0.0003125 m/s²
By using Equation of motion,
→ v = u + at
Time taken, t = [tex]\frac{v-u}{a}[/tex]
= [tex]\frac{6-0}{0.0003125}[/tex]
= 19200 s or,
= 5.3 hours
Thus the above response is correct.
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