The normal force on the sled is 190.9 N.
Explanation:
For this problem, we have to analyze the forces acting along the vertical direction on the sled.
We have:
- The weight of the sled, W = mg, acting downward, where
m = 19.7 kg is the mass of the sled
g = 9.8 m/s^2 is the acceleration of gravity
- The normal force on the sled, N, acting upward
- The vertical component of the pulling force, [tex]F sin \theta[/tex], acting upward, where
F = 42.0 N is the magnitude of the force
[tex]\theta=3.0^{\circ}[/tex] is the angle
Since the sled is in equilibrium along the vertical direction, the equation of the force is
[tex]F sin \theta + N - mg = 0[/tex]
And solving for N, we find
[tex]N=mg -Fsin \theta = (19.7)(9.8) - (42.0)(sin 3)=190.9 N[/tex]
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