Respuesta :
Answer:
Volume, [tex]V=3.78\times 10^{-6}\ m^3[/tex]
Explanation:
It is given that, an alloy that is one karat gold contains a weight of pure gold that is one part in twenty-four.
14 karat of gold contains a weight of pure gold is, [tex]\dfrac{14}{24}=0.58[/tex]
The necklace contains 58% of gold, the weight of gold is :
[tex]W=0.58\times 1.25=0.725\ N[/tex]
The mass of gold is, [tex]m=\dfrac{0.725}{9.8}=0.073\ kg[/tex]
Let V is the volume of fold in 14 karat. Using the formula of density to find it as :
[tex]d=\dfrac{m}{V}[/tex]
[tex]V=\dfrac{m}{d}[/tex]
d is the density of gold, [tex]d=19300\ kg/m^3[/tex]
[tex]V=\dfrac{0.073\ kg}{19300\ kg/m^3}[/tex]
[tex]V=3.78\times 10^{-6}\ m^3[/tex]
So, the volume of fold necklace is [tex]3.78\times 10^{-6}\ m^3[/tex]. Hence, this is the required solution.
