contestada

If you were to separate all of the electrons and protons in 1 g (0.001 kg) of matter, you’d have about 96,000 C of positive charge and the same amount of negative charge. If you placed these charges 4.5 m apart, how strong would the attractive force between them be?

Respuesta :

cjmejiab

Answer:

[tex]F = 4.096*10^18N[/tex]

Explanation:

To solve this problem we need to apply the concept relate to Coulomb's law.

We know that the Force given by Coulomb is

[tex]F = K \frac{q_1q_2}{r^2}[/tex]

Where ,

F= electrostatic force

q= electric charge

r= distance between charge centers

k= Coulomb constant = [tex]9.0*10^9 Nm^2/c^2[/tex]

We have the values only to replace in the equation, then we have,

[tex]F = (9.0*10^9)\frac{96000*96000}{4.5^2}[/tex]

[tex]F = 4.096*10^18N[/tex]

Otras preguntas