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If an object of mass m1 = 0.55 ???????? is sliding without friction in the +x-direction on a level surface at a speed of ????1 = 0.72 m/???? and it collides with a stationary object of mass m1 = 0.55 ????????, determine the total initial and total final momenta (before and after the collision) as well as the total initial and final Mechanical Energy (before and after the collision) for a perfectly elastic collision.

Respuesta :

Answer:

[tex]ME = 0.14 J[/tex]

[tex]P = 0.396 kg m/s[/tex]

Explanation:

As we know that for perfectly elastic collision total mechanical energy is always conserved

so we will have

[tex]ME = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2[/tex]

[tex]ME = \frac{1}{2}0.55(0.72^2) + \frac{1}{2}0.55(0^2)[/tex]

[tex]ME = 0.14 J[/tex]

now we also know that total moment of the system is conserved in any collision because there is no external force on it

so we will have

[tex]P = m_1v_1 + m_2v_2[/tex]

[tex]P = 0.55(0.72) + 0[/tex]

[tex]P = 0.396 kg m/s[/tex]

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