Answer:
Mass = 30.104 g
Explanation:
Given data:
Volume of Cl₂ = 8.80 L
Pressure = 890 torr (890/760 = 1.17 atm)
Temperature = 23°C (23+273 = 296K)
Mass of chlorine = ?
Solution:
PV = nRT
n = PV/RT
n = 1.17 atm × 8.80 L / 0.0821 atm. L. k⁻¹.mol⁻¹ × 296K
n = 10.296 atm. L / 24.30 atm. L.mol⁻¹
n = 0.424 mol
Mass of chlorine:
Mass = number of moles × molar mass
Mass = 0.424 mol × 71 g/mol
Mass = 30.104 g
