Answer:
The width of the piece of construction paper is 12 inches.
Step-by-step explanation:
The length of the construction paper= 4 3/16 in log
[tex]4\frac{3}{16} = 4 + \frac{3}{16} = 4 + 0.1875 = 4.1875[/tex]
⇒Length of the paper = 4.1875 inches
Let the width of the paper = w inches
The area of the paper = 50 1/4 sq. inches.
[tex]50\frac{1}{4} = 50 + \frac{1}{4} = 50 + 0.25 = 50.25[/tex]
⇒Area of the paper = 50.25 sq. inches
Now, Area of the paper = LENGTH x WIDTH
or, 50.25 sq. inches = 4.1875 inches x w
⇒ w = 50.25 / 4.1875 = 12 in
or, w = 12 in
Hence, the width of the piece of construction paper is 12 inches.
