Answer:
a) East direction and magnitude [tex]E_{mf}=4.509x10^{-4} V[/tex]
Explanation:
The magnetic field is in the north direction and have 65 angle so to form a 90 angle the east direction for the generate the maximum motional Emf
check:
[tex]E_{mf}=\beta*l*v[/tex]
[tex]v=70\frac{km}{h}*\frac{1000m}{1km}*\frac{1h}{3600s}=19.4\frac{m}{s}[/tex]
[tex]E_{mf}=\beta*cos(65)*l*v[/tex]
now taking just the magnetic field to determinate the maximum Emf
[tex]E_{mf}=50uT*cos(65)*1.1m*19.4\frac{m}{s}[/tex]
[tex]E_{mf}=50x10^{-6}T*0.4226*1.10m*19.4\frac{m}{s}[/tex]
[tex]E_{mf}=4.509x10^{-4} V[/tex]
