Answer:
Part a) [tex]T(d)=2d+30[/tex]
Part b) [tex]T(6)=42\ minutes[/tex]
Step-by-step explanation:
Part a) Write an equation for T (d)
Let
d ----> the number of days
T ---> the time in minutes of the treadmill
we know that
The linear equation in slope intercept form is equal to
[tex]T=md+b[/tex]
where
m is the slope or unit rate
b is the y-intercept or initial value
In this problem we have
The slope or unit rate is
[tex]m=2\ \frac{minutes}{day}[/tex]
The y-intercept or initial value is
[tex]b=30\ minutes[/tex]
substitute
[tex]T(d)=2d+30[/tex]
Part b) Find T (6), the minutes he will spend on the treadmill on day 6
For d=6
substitute in the equation and solve for T
[tex]T(6)=2(6)+30[/tex]
[tex]T(6)=42\ minutes[/tex]