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The proof shows that ABCD is a rectangle. Which of the following is the missing reason?

A.Angle-side-angle postulate
B.Side-angle-side postulate
C.Angle-angle-side postulate
D.Side-side-side postulate

The proof shows that ABCD is a rectangle Which of the following is the missing reason AAnglesideangle postulate BSideangleside postulate CAngleangleside postula class=

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Answer:

Side-side-side postulate

Step-by-step explanation:

In the first statement, we are given that AC = BD ....... (1){It is given}

Now, in the second statement, we are given that AB = DC ...... (2){ Because the parallelogram has equal opposite sides}

Now, again we are given that AD = DA ........... (3) {From the symmetric property}

Now, conditions (1), (2), and (3) are applicable to say that Δ ABD and Δ ACD are congruent.

Since there are three sides involved to say Δ ABD ≅ Δ ACD, so it is by Side-side-side postulate. (Answer)

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