Answer:
We fail to reject null hypothesis.
Step-by-step explanation:
Consider the provided information.
The mean daily coffee consumption for U.S. residents as 1.65 cups. Assume that a sample of 38 people from a North Carolina city consumed a mean of 1.84 cups of coffee per day, with a standard deviation of 0.85 cups.
[tex]H_0:\mu=1.65[/tex]
[tex]Ha0:\mu\neq 1.65[/tex]
According to the formula: [tex]t=\frac{\bar x-\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
Substitute n=38, x = 1.84, μ = 1.65 and σ = 0.85 in above formula.
[tex]t=\frac{1.84-1.65}{\frac{0.85}{\sqrt{38}}}[/tex]
[tex]t=1.38[/tex]
Now find degree of freedom (df)
df=n-1=37
α = 0.025
The appropriate t value with df =37 and α = 0.025 is 2.026
The t value which we calculated is less than 2.026, Hence, we fail to reject null hypothesis.
