1. Predict the charge each of the following atoms would have as an ion – if more than one charge is possible, include each different charge (use your cheat sheet).

a. Cl​​b. Na​c. Mg​d. O





e. Al​f. Fe​g. Cu​h. Zn

Respuesta :

Neetoo

Answer:

Explanation:

The chlorine is present in group 17. It has seven valance electrons. It accept one electron to complete the octet and show -1 charge and from anion.

Cl⁻

Sodium is present in group one. It alkali metal. It loses one valance electron and show +1 charge. It form sodium cation.

Na⁺

Magnesium is present in group two. It loses its two valance electrons and show +2 charge. It form magnesium cation.

Mg⁺²

Oxygen is present in group 16. It has six valance electrons. It require two electrons to complete the octet and show -2 charge.

O⁻²

Aluminium is present in group 13. it has three valance electrons. It loses its three valance electrons and show +3 oxidation state

Al⁺³ (most common)

others = Al⁺¹,  Al⁺²

Iron is present on group eight.

Fe⁺² , Fe⁺³ (most common)

others = Fe⁺⁴, Fe⁺⁵

Copper is present in group eleven.

Cu⁺¹ Cu⁺²

other = Cu⁺³

Zinc is present in group twelve. -2, 0, +1 , +2

Zn⁻², Zn⁺¹, Zn⁺²