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A car is driven at constant speed over a circular hill and then into a circular valley with the same radius. At the top of the hill, the normal force on the driver from the car seat is 0. The driver's mass is 77.8 kg. What is the magnitude of the normal force on the driver from the seat when the car passes through the bottom of the valley?

Respuesta :

Manetho

Answer:

therefore normal reaction on the driver from the seat when the car passes through the bottom of the valley= 1520.55 N

Explanation:

let speed be v

at top of hill

mg-N = mv^2/R   ( N=0 at the top of the hill)

==> mg=mv^2/R

at bottom

N-mg=mv^2/R

therefore,

N = 2mg = 2*77.8*9.81= 1520.55 N

therefore normal reaction on the driver from the seat when the car passes through the bottom of the valley= 1520.55 N

onyebuchinnaji

The normal force on the driver at the bottom of the valley is 1,524.9 N.

The given parameters;

  • mass of the driver, m = 77.8 kg

The normal force on the driver at the top of the hill will be determined by applying the principle of tensional force on a body at top of a vertical path in a circle;

[tex]N = \frac{mv^2}{r} - mg\\\\0 = \frac{mv^2}{r} - mg\\\\\frac{mv^2}{r} = mg \ \ -----(1)[/tex]

The normal force on the driver at the bottom of the valley will be determined by applying the principle of tensional force on a body at bottom  of a vertical path in a circle;

[tex]N_b = \frac{mv^2}{r} + mg[/tex]

[tex]N_b = 2mg[/tex]

[tex]N_b = 2 (77.8 \times 9.8) \\\\N_b = 1,524.9 \ N[/tex]

Learn more here: https://brainly.com/question/14109863

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