Answer:
d) v1 = v2 = v3
Explanation:
This can be answered using conservation of energy. We calculate the mechanical energy E=K+U (sum of kinetic and gravitational potential energies) at the original and final points, and impose they are equal.
At the original point we have, for the three balls:
[tex]E_i=K_i+U_i=\frac{mv_i^2}{2}+mgh_i=\frac{mv^2}{2}+mgh[/tex]
At the final point we have, for the three balls:
[tex]E_f=K_f+U_f=\frac{mv_f^2}{2}+mgh_f=\frac{mv_f^2}{2}[/tex]
Since we have [tex]E_i=E_f[/tex], and [tex]E_i[/tex] is the same for all balls, then [tex]E_f[/tex] is the same for all balls, which means that [tex]v_f[/tex], the final velocity, is the same for all balls.
The final velocity of all 3 balls will be the same. Option D is correct.
v1 = v2 = v3
The energy neither be produced nor be destroyed. The sum of the initial kinetic energy and potential energy will be equal to the sum of the final kinetic and potential energy.
[tex]\dfrac 12 mv_i^2 +mgh_i = \dfrac 12 mv_f^2 +mgh_f [/tex]
Where,
[tex]m[/tex] - mass
[tex]v[/tex] - velocity
[tex]g [/tex]- gravitational acceleration
[tex]h[/tex] - height
Since the ball is moving hence the final potential energy will be zero,
[tex]\dfrac 12 mv_i^2 +mgh_i = \dfrac 12 mv_f^2 [/tex]
As given in the question, all balls have the same initial kinetic energy,
Therefore, the final velocity of all 3 balls will be the same.
Learn more about the Conservation of energy:
https://brainly.com/question/13819027
