Respuesta :
Answer:
[tex]PF=2400[/tex] kVA units.
Step-by-step explanation:
Given : In a parallel circuit et= 240 v ,r = 30 ohms and xl = 40 ohms.
To find : What is the power factor?
Solution :
In a parallel rl circuit we have,
Total voltage, et= 240 Volts,
Resistance, r= 30 ohm,
Inductive Reactance, xl= 40 ohm.
In parallel circuit, the voltage across resistor and inductor remains same.
i.e. vr = vl= v= 240 Volts
Using Ohm's Law,
The current across resistor would be [tex]ir=\frac{v}{r}[/tex]
[tex]ir=\frac{240}{30}[/tex]
[tex]ir=8\ amp[/tex]
Using Ohm's Law,
The current across inductor would be [tex]il=\frac{v}{xl}[/tex]
[tex]il=\frac{240}{40}[/tex]
[tex]il=6\ amp[/tex]
Now, Total current would be [tex](it)^2= (ir)^2+ (il)^2[/tex]
[tex](it)^2= (8)^2+ (6)^2[/tex]
[tex](it)^2= 64+36[/tex]
[tex](it)^2= 100[/tex]
[tex]it= 10[/tex]
The voltage is 240 V and current is A= 10 amp
The power factor is [tex]PF=V\times A[/tex]
[tex]PF=240\times 10[/tex]
[tex]PF=2400[/tex] kVA units.
