Answer: rate of disappearance of hydrogen = [tex]-\frac{1d[H_2]}{2dt}[/tex] rate of disappearance of oxygen = [tex]-\frac{1d[O_2]}{1dt}[/tex]
rate of appearance of water = [tex]+\frac{1d[H_2O]}{2dt}[/tex]
Explanation:
Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.
[tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex]
The rate law is:
[tex]Rate=k[H_2]^2[O_2]^1[/tex]
k= rate constant
The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.
rate of disappearance of hydrogen= [tex]-\frac{1d[H_2]}{2dt}[/tex]
rate of disappearance of oxygen = [tex]-\frac{1d[O_2]}{1dt}[/tex]
rate of appearance of water = [tex]+\frac{1d[H_2O]}{2dt}[/tex]