Answer:
The charge flows in coulombs is
[tex]dq=1.843x10^{-5}C[/tex]
Explanation:
The current magnitude of current is given by the resistance and the induced Emf as:
[tex]I=N*\frac{dF}{Rdt}[/tex]
[tex]\frac{dq}{dt}=\frac{dF}{Rdt}=dq=N*\frac{dF}{R}[/tex]
[tex]dq=\frac{N*\beta*A*(Cos(\alpha_f)-Cos(\alpha_i}{R}[/tex]
[tex]N=1300[/tex], [tex]\beta=0.703[/tex], [tex]A=\pi*r^2=\pi*0.10^2=0.01\pi m^2[/tex], [tex]R=99.4+202=301.4[/tex]Ω
[tex]\alpha_f=14.6[/tex],[tex]\alpha_i=165.4[/tex]
Replacing :
[tex]dq=\frac{1300*0.703x10^{-4}*0.01\pi*(0.9667-(-0.9667))}{202+99.4}[/tex]
[tex]dq=1.843x10^{-5}C[/tex]
