Answer:
40.293 L
Explanation:
So let's count how much moles of N2 gas we will obtain.
2NaN3(s) → 2Na(l) + 3N2(g)
n(N2)=3/2n(NaN3)=3/2*m(NaN3)/M(NaN3)=3/2*71.4/65.01=1.65 mol
So now we need to use the ideal gas law to count liters.
All numbers must be in Si system
pV=nRT
V=(nRT)/p
V=(1.65*8.314*298)/101457.5=0.040293m3=40.293 L