Answer:
O'(-2,-2) and U'(0,0).
Step-by-step explanation:
ΔTOY has coordinates T (−3, 4), O (−4, 1), and Y (−2, 3).
It is given that a translation maps point T to T' (−1, 1).
The x-coordinate increased by 2 and y-coordinate decreased by 3. So, the rule of translation is
[tex](x,y)\rightarrow (x+2,y-3)[/tex]
The coordinates of O' and Y' under this translation.
[tex]O(-4,1)\rightarrow O'(-4+2,1-3)=O'(-2,-2)[/tex]
[tex]Y(-2,3)\rightarrow Y'(-2+2,3-3)=U'(0,0)[/tex]
Therefore, the coordinates of O' and Y' under this translation are O'(-2,-2) and U'(0,0).
